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Rule in the 2048 game (Developers)

posted by jadoxa Homepage E-mail, Queensland, Australia, 25.07.2022, 03:22

> What the function does: in the random free cell on the board places a new
> cell - which in the 90% probability is the cell "2" and in the 10%
> probability cell "4".
> My question is: This is the same algorithm like in the original
> implementation?

Yes.

GameManager.prototype.addRandomTile = function() {
    if (this.grid.cellsAvailable()) {
        var e = Math.random() < .9 ? 2 : 4,
            t = new Tile(this.grid.randomAvailableCell(), e);
        this.grid.insertTile(t)
    }
},

 

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