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I made my own DOS implementation (Announce)

posted by tom Homepage, Germany (West), 22.03.2024, 17:32
(edited by tom on 23.03.2024, 07:28)

> > Yes, absolutely.
> > It allows to allocate some memory (and copy resident code to it) which
> will
> >
> > remain resident when the program calls exit().
> > There are other ways to stay TSR; but this has a couple of advantages.
>
> That does not require modifying the struct manually.
 What other way would you propose?
>
> It is also not documented that the owner of a memory block changes when its
> size is changed.
I know. But MSDOS does exactly this.


> But I can easily change the behaviour of the kernel so
> that it works like that. Currently it does not change the owner.
>
> The way the memory allocation structs are done in MS-DOS is inefficient and
> makes it slow to traverse the memory allocations backwards, especially when
> there is a large number of allocated memory blocks.
 Sure.

OTOH, you could place Type ('M' or 'Z'); owner and size in The proper location to solve the *this* problem.

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